The perimeter of a rectangle is 50 units, and its length is 14 units. What is the width of the rectangle?

Correct Answer : 11

P=2×( length + width )

Given that the perimeter (P) of the rectangle is 50 units and the length is 14 units, we can substitute these values into the formula and solve for the width (W):

50 units=2×(14 units +width)

First, we'll simplify the equation:

50 units=28 units+2×width

50 units−28 units=2×width

22 units=2×width

Now, we'll divide both sides by 2 to isolate the width:

width=22/2 units​

width=11 units

Therefore, the width of the rectangle is 11 units.

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